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Page 1221 – Comments for “Discuss: Final Grade Calculator”

Comments (Page 1221)

me
Tue, 19 Nov 2019 16:40:51 GMT

thats not what i got ) :/

customwritings
Tue, 19 Nov 2019 16:16:51 GMT

We can always help you with boosting your GPA, even when the situation seem to be critical

joe
Tue, 19 Nov 2019 16:09:36 GMT

I Figured Out Who Joe Is On My Exam. But DONT ASK ME.

rogerisganggang
Tue, 19 Nov 2019 06:38:31 GMT

ROGERS GONNA BUY US ALL PIZZA

Stressed Student
Tue, 19 Nov 2019 06:10:18 GMT

Ok so I have an 84.1989 in my music class right now. A research paper due in four days that I have not started yet worth 100 points and 20% of my grade. Can I not do it and still pass the class with at least a 70%?

Roger: Probably not?

oh no
Tue, 19 Nov 2019 05:23:22 GMT

i just got a 0 on my last test

Anonymous
Tue, 19 Nov 2019 04:24:15 GMT

Y0 ROGER! I have a 86 in science and I was wondering what would happen to my grade if i suddenly got a 30?

Roger: I guess it would go down?

0K B00M3R
Tue, 19 Nov 2019 03:04:43 GMT

OKAY BOOMER

I had to....
Tue, 19 Nov 2019 02:24:25 GMT

If x⁴ + ax² + bx + 2 divided by (x²+1) leaves a remainder of -x + 1, then:
(x²+1) divides x⁴ + ax² + bx + 2 - (-x +1) = x⁴ + ax² + (b + 1) + 1 exactly.
Since (x²+1) = (x + i)(x - i) this tells us (x - i) also divides x⁴ + ax² + (b + 1)x + 1 and, by the Polynomial Remainder Theorem, i is a zero.

Substituting x = i in to x⁴ + ax² + (b + 1)x + 1 = 0 gives:
1 - a + (b + 1)i + 1 = 0
And by comparing real and imaginary parts we get a = 2, and b = -1If x⁴ + ax² + bx + 2 divided by (x²+1) leaves a remainder of -x + 1, then:
(x²+1) divides x⁴ + ax² + bx + 2 - (-x +1) = x⁴ + ax² + (b + 1) + 1 exactly.
Since (x²+1) = (x + i)(x - i) this tells us (x - i) also divides x⁴ + ax² + (b + 1)x + 1 and, by the Polynomial Remainder Theorem, i is a zero.

Substituting x = i in to x⁴ + ax² + (b + 1)x + 1 = 0 gives:
1 - a + (b + 1)i + 1 = 0
And by comparing real and imaginary parts we get a = 2, and b = -1If x⁴ + ax² + bx + 2 divided by (x²+1) leaves a remainder of -x + 1, then:
(x²+1) divides x⁴ + ax² + bx + 2 - (-x +1) = x⁴ + ax² + (b + 1) + 1 exactly.
Since (x²+1) = (x + i)(x - i) this tells us (x - i) also divides x⁴ + ax² + (b + 1)x + 1 and, by the Polynomial Remainder Theorem, i is a zero.

kenny gorl
Tue, 19 Nov 2019 00:01:17 GMT

literally only reason I ever passs any of my finals god bless.

Cool person
Mon, 18 Nov 2019 23:45:35 GMT

Omg ignore my previous comment its dumb

Cool person
Mon, 18 Nov 2019 23:44:51 GMT

roger rhymes with dodger

ace
Mon, 18 Nov 2019 20:39:59 GMT

i did the math, honestly if you get a 100 on the final the most it would do is bring the grade up five percent. Only if you have a 20% for finals. For example, if you have a 85 (i got a 100 on the final) it brought me up exactly to a 90.

Trimester Gang
Mon, 18 Nov 2019 20:39:19 GMT

This post was made by trimester gang

Roger
Mon, 18 Nov 2019 20:26:48 GMT

Roger would u sniff her seat?

Roger: I don’t get it.

nick gurr
Mon, 18 Nov 2019 19:57:59 GMT

bruh i want 5 more percent but its not the final is 20% of my grade and it isnt enough :((((((((((((((((((

Grateful Student
Mon, 18 Nov 2019 18:53:54 GMT

@Arvi
Sorry but I love him

Not trying to start a war. Can we be friends I think you are great!

Failure
Mon, 18 Nov 2019 18:15:04 GMT

lol i have all Bs in the second quarter currently and i really want all As for my semester grade but if i dont get those Bs up and do well on the final im screwed :(

Peppa Pig
Mon, 18 Nov 2019 17:18:24 GMT

Juicy Juicy
Skills

thankful
Mon, 18 Nov 2019 17:15:41 GMT

I love you roger, do you love me too?

Roger: Sure

DEPRESSION
Mon, 18 Nov 2019 17:13:40 GMT

I CANT DO THIS!!!!!! IM BOOMER ON YOU SMARTS!!!!!!!!!!DANK MEMES RULE!!!!!!
Love ya Roger your a life saver
#dontstudy
#rogerlove

Hi
Mon, 18 Nov 2019 16:41:11 GMT

Hello

Dysin
Mon, 18 Nov 2019 16:37:52 GMT

My grade is 64% now if i got a 51% on a test whats my final grade.

Roger: How much is your test worth?

i am died
Mon, 18 Nov 2019 16:05:36 GMT

catch me doing this instead of actually studying for the exam that brought me hereeeeee
hMm sTrANgE
owo

Evan
Mon, 18 Nov 2019 14:56:31 GMT

Instead of studying for my exams I’ve just been reading some roger comments.

A student
Mon, 18 Nov 2019 14:03:41 GMT

I hate how like 4 grades in the entire cycle are worth 50% more than the like 30 other grades.

$
Mon, 18 Nov 2019 03:23:58 GMT

its that time of year to look up final grade calculator ;(

soph
Mon, 18 Nov 2019 03:23:06 GMT

hey

Will H
Mon, 18 Nov 2019 01:35:12 GMT

Hi all,
So I am currently enrolled in AP Calc and my lack of focus has resulted in me currently having a 56% in the class. My parents are on my tail about getting the grade back up, but I lack the dedication to get As on the tests. Roger, I am asking you personally. Is there any way I can get my grade up to an A by the end of the semester by getting Cs on my tests?
With love,
Will Huntington

Roger: Sounds unlikely.

Help
Mon, 18 Nov 2019 01:29:53 GMT

Hi guys. I just got a 2% on my calculus test (.5/25). My grades down to a 32% total. Is it possible to get my grade back to an A? The final is worth 5% and we have 2 tests left. All of them are weighted the same. Please help! I chose not to drop the class because I have hope of securing the A.

Thanks,
Jack Barber

Roger: Try the calculator mode labeled “I need something else”. It should be able to answer your question.

Scared
Mon, 18 Nov 2019 01:29:30 GMT

my life's easy. i be chilln

Anonymous
Sun, 17 Nov 2019 22:04:56 GMT

ur mom

joshy
Sun, 17 Nov 2019 20:35:42 GMT

Yo, I just got a 34% on a geometry test, if i get a 100% on the final will I be able to raise my 47% grade to a C?

Roger: Sounds unlikely, but it depends on how much your final is worth.

Big Box
Sun, 17 Nov 2019 18:55:53 GMT

iF i GeT a 100 pErCeNt oN mY fInAl wOuLd tHaT gIvE mE a GoOd gRaDe??????????

Sophie
Sun, 17 Nov 2019 16:14:29 GMT

Music Theory is the reason I cry at night

Arvi
Sun, 17 Nov 2019 08:48:34 GMT

@Grateful Student

Stop trying to steal mah man.

Cool person
Sun, 17 Nov 2019 02:40:27 GMT

If i get 100% on my math test and my current grade is 86%, howmuch will that boost my grade at?

Roger: It depends on how much your test is worth.

anon
Sat, 16 Nov 2019 21:02:14 GMT

trimester system got us good

Anonymous
Sat, 16 Nov 2019 18:14:21 GMT

why are people on here
It's fricken november not even finals or midterms yet

Yeet
Sat, 16 Nov 2019 17:08:48 GMT

This is some snazzy aid

lols
Sat, 16 Nov 2019 03:47:43 GMT

SO I NEED A 95 % BUT I HAVE 87% IS THAT POSSIBLE

AP Anat and Phys = DEATH!!!!!
Sat, 16 Nov 2019 01:32:48 GMT

LITERALLY thought I was gonna fail! Thank you Roger!

Roger: You’re welcome!

someone
Sat, 16 Nov 2019 01:00:39 GMT

berkeley is killing me :/

ok boomer
Fri, 15 Nov 2019 23:11:38 GMT

Some of y'all in this comment section be flexing your intelligence knowing damn well some people may not have the same circumstances or capabilities as you, and that's some real boomer energy right there.

Emmy
Fri, 15 Nov 2019 23:09:12 GMT

I have a
92 in class and if I get a 95 what will my grade be

thanks
Fri, 15 Nov 2019 23:06:48 GMT

Hi Roger, thanks so much for your website, it's a lifesaver!

Roger: Glad to help!

Anonymous
Fri, 15 Nov 2019 22:49:24 GMT

What grade will I need to make on my final exam (worth 21%) to get at least a B in the class if I got a 68 on my first exam, 94 on my second exam, 56 on my third exam (each worth 16% of total grade) and the final replaces the lowest grade.

I have a 98 average for homework (worth 15% total grade)
A 99 average for clicker questions (worth 8%)
and a 100 average for Group assignments (worth 8%)

Roger: Your current overall grade is a 82.9% (or a 89.7%, if you ignore your lowest test grade). You’ll need to average at least a 63.4% on your final to get a 80% overall.

Anonymous
Fri, 15 Nov 2019 22:35:45 GMT

By minidee on Sun, 04/27/2008 - 18:09
gas phase proceeds by the following reaction:

Cl2(g) -> 2 Cl(g) k1, fast
Cl(g) + CO(g) -> COCl(g) k2, fast
COCl(g) + Cl2(g) -> COCl2(g) + Cl(g) k3, slow
2Cl(g) ---> Cl2 k4, fast

overall reaction: CO(g) + Cl2(g) ---> COCl2(g)

a. write rate law for this reaction.
b. which species are intermediates?

I know the rate law is Rate=k[CO][Cl2] and the intermediates are cl2, cl, cocl, 2cl.

but why does the textbooks go through all those k1/k-1 and k2/k-2 steps to get to the overall reaction, the rate law, which is already in front of our faces? And how do you do it?

m
Fri, 15 Nov 2019 22:10:53 GMT

m

Anonymous
Fri, 15 Nov 2019 20:45:46 GMT

hey, is this a robot

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